What is the answer to log_{5}(x^2)+9=2 ?

The answer to log_{5}(x^2)+9=2 is x= 1/(125sqrt(5)),x=-1/(125sqrt(5))

Solve for x: log_{5}(x^2)+9=2

The solution is x= 1/(125sqrt(5)),x=-1/(125sqrt(5))

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lo g_{5} (x^{2}) + 9 = 2

x = \frac{1}{125 5}, x = - \frac{1}{125 5}

Decimal

x = 0.00357 \dots, x = - 0.00357 \dots

Solution steps

lo g_{5} (x^{2}) + 9 = 2

Move

9

to the right side

lo g_{5} (x^{2}) = - 7

Apply log rules

x^{2} = \frac{1}{78125}

Solve

x^{2} = \frac{1}{78125} : x = \frac{1}{125 5}, x = - \frac{1}{125 5}

x = \frac{1}{125 5}, x = - \frac{1}{125 5}

Verify Solutions:

x = \frac{1}{125 5}

True

, x = - \frac{1}{125 5}

True

The solutions are

x = \frac{1}{125 5}, x = - \frac{1}{125 5}

lo g_{6} (3 x) - lo g_{6} (2 x) + 4 = 0

3 ln (x - 6) = - 3

lo g_{4} (x - 3) = 1

ln (t + 5) = 0

2 + 3 ln (x) = 12

What is the answer to log_{5}(x^2)+9=2 ?
The answer to log_{5}(x^2)+9=2 is x= 1/(125sqrt(5)),x=-1/(125sqrt(5))
Solve for x: log_{5}(x^2)+9=2
The solution is x= 1/(125sqrt(5)),x=-1/(125sqrt(5))