What is the answer to log_{2}(5)+log_{2}(x-2)=1 ?

The answer to log_{2}(5)+log_{2}(x-2)=1 is x= 12/5

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log_{2}(5)+log_{2}(x-2)=1

lo g_{2} (5) + lo g_{2} (x - 2) = 1

x = \frac{12}{5}

Decimal Notation

x = 2.4

Solution steps

lo g_{2} (5) + lo g_{2} (x - 2) = 1

Move

lo g_{2} (5)

to the right side

lo g_{2} (x - 2) = 1 - lo g_{2} (5)

Apply log rules

x - 2 = \frac{2}{5}

Solve

x - 2 = \frac{2}{5} : x = \frac{12}{5}

x = \frac{12}{5}

Verify Solutions:

x = \frac{12}{5}

True

The solution is

x = \frac{12}{5}

10 \cdot lo g_{10} (x) = 3

0.35 = ln (y)

- x + ln (x) = c

ln (x) + ln (x - 2) = ln (5 x)

lo g_{3} (x) - lo g_{3} (9) = 4

What is the answer to log_{2}(5)+log_{2}(x-2)=1 ?
The answer to log_{2}(5)+log_{2}(x-2)=1 is x= 12/5
Solve for x: log_{2}(5)+log_{2}(x-2)=1
The solution is x= 12/5