What is the answer to log_{3}(9x-2)=2+4log_{9}(x) ?

The answer to log_{3}(9x-2)=2+4log_{9}(x) is x= 2/3 ,x= 1/3

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log_{3}(9x-2)=2+4log_{9}(x)

lo g_{3} (9 x - 2) = 2 + 4 lo g_{9} (x)

x = \frac{2}{3}, x = \frac{1}{3}

Decimal Notation

x = 0.66666 \dots, x = 0.33333 \dots

Solution steps

lo g_{3} (9 x - 2) = 2 + 4 lo g_{9} (x)

Apply log rules

9 x - 2 = 9 x^{2}

Solve

9 x - 2 = 9 x^{2} : x = \frac{2}{3}, x = \frac{1}{3}

x = \frac{2}{3}, x = \frac{1}{3}

Verify Solutions:

x = \frac{2}{3}

True

, x = \frac{1}{3}

True

The solutions are

x = \frac{2}{3}, x = \frac{1}{3}

lo g_{10} (m) = 2003

lo g_{x + 2} (x + 2) = - 2

14 lo g_{1} (x^{2} - x - 6) = 1

lo g_{10} (\frac{x ^{2}}{x - 1}) = 3

z^{2} - 2 z + i = 0

What is the answer to log_{3}(9x-2)=2+4log_{9}(x) ?
The answer to log_{3}(9x-2)=2+4log_{9}(x) is x= 2/3 ,x= 1/3
Solve for x: log_{3}(9x-2)=2+4log_{9}(x)
The solution is x= 2/3 ,x= 1/3