What is the answer to (2+xi)+(y+3i)=7+4i ?

The answer to (2+xi)+(y+3i)=7+4i is x=1,y=5

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(2+xi)+(y+3i)=7+4i

(2 + x i) + (y + 3 i) = 7 + 4 i

x = 1, y = 5

Solution steps

(2 + x i) + (y + 3 i) = 7 + 4 i

Rewrite

(2 + x i) + (y + 3 i)

in standard complex form:

(2 + y) + (x + 3) i

(2 + y) + (x + 3) i = 7 + 4 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[2 + y = 7 x + 3 = 4]

[2 + y = 7 x + 3 = 4] : x = 1, y = 5

x = 1, y = 5

(a + bi)^{2} = 3 + 4 i

∣ z - i ∣ = 1

x^{2} = 4 i

3 x + 2 i y - i x + 5 y = 7 + 5 i

(a + bi)^{2} = - 5 + 12 i

What is the answer to (2+xi)+(y+3i)=7+4i ?
The answer to (2+xi)+(y+3i)=7+4i is x=1,y=5