What is the answer to (2-i)^2-(2-yi)=x+5i ?

The answer to (2-i)^2-(2-yi)=x+5i is x=1,y=9

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(2-i)^2-(2-yi)=x+5i

(2 - i)^{2} - (2 - y i) = x + 5 i

x = 1, y = 9

Solution steps

(2 - i)^{2} - (2 - y i) = x + 5 i

Expand

(2 - i)^{2} - (2 - y i) : 1 + i (- 4 + y)

1 + i (- 4 + y) = x + 5 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[1 = x - 4 + y = 5]

[1 = x - 4 + y = 5] : x = 1, y = 9

x = 1, y = 9

∣ z - (1 - i) ∣ = 2

a - bi = i (a + bi)

∣ z - 1 + i ∣ = 3

\frac{z + 1}{z - 1} = 2 + i^{25}

(x + y) + (x - y) i = 3 + i

What is the answer to (2-i)^2-(2-yi)=x+5i ?
The answer to (2-i)^2-(2-yi)=x+5i is x=1,y=9