What is the answer to (a-1)+(b+3)i=5+8i ?

The answer to (a-1)+(b+3)i=5+8i is a=6,b=5

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(a-1)+(b+3)i=5+8i

(a - 1) + (b + 3) i = 5 + 8 i

a = 6, b = 5

Solution steps

(a - 1) + (b + 3) i = 5 + 8 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[a - 1 = 5 b + 3 = 8]

[a - 1 = 5 b + 3 = 8] : a = 6, b = 5

a = 6, b = 5

(x - i y)^{2} = 4 (x + i y)

z^{2} + (2 i - 3) z + 5 - i = 0

z^{2} - (5 - 4 i) z + (3 - 11 i) = 0

z^{2} + 2 \cdot i \cdot z - 1 - i = 0

x^{2} - 2 (1 + i) x + (2 i - 1) = 0

What is the answer to (a-1)+(b+3)i=5+8i ?
The answer to (a-1)+(b+3)i=5+8i is a=6,b=5