What is the answer to (x+yi)(1+2i)=-1+8i ?

The answer to (x+yi)(1+2i)=-1+8i is x=3,y=2

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(x+yi)(1+2i)=-1+8i

(x + y i) (1 + 2 i) = - 1 + 8 i

x = 3, y = 2

Solution steps

(x + y i) (1 + 2 i) = - 1 + 8 i

Expand

(x + y i) (1 + 2 i) : (x - 2 y) + i (y + 2 x)

(x - 2 y) + i (y + 2 x) = - 1 + 8 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x - 2 y = - 1 y + 2 x = 8]

[x - 2 y = - 1 y + 2 x = 8] : x = 3, y = 2

x = 3, y = 2

\frac{2 - i}{z - 1} = 1 + 2 i

5 x + 6 i = - 20 + 2

x^{2} - 3 i x + (- 3 + i) = 0

z^{2} - (3 + 6 i) z - (4 + 6 i) = 0

25 - 49 i = x^{2} + y^{2} i

What is the answer to (x+yi)(1+2i)=-1+8i ?
The answer to (x+yi)(1+2i)=-1+8i is x=3,y=2