What is the answer to 2x-y+(3y-2x)i=2-2i ?

The answer to 2x-y+(3y-2x)i=2-2i is x=1,y=0

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2x-y+(3y-2x)i=2-2i

2 x - y + (3 y - 2 x) i = 2 - 2 i

x = 1, y = 0

Solution steps

2 x - y + (3 y - 2 x) i = 2 - 2 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[2 x - y = 2 3 y - 2 x = - 2]

[2 x - y = 2 3 y - 2 x = - 2] : x = 1, y = 0

x = 1, y = 0

z^{2} - 3 + 4 i = 0

x^{2} + (2 - 2 i) x + 3 - 6 i = 0

a^{2} - b^{2} - a - bi = 1

(2 x - 3 y i) (1 - 2 i) = 1 - 4 i

x + i y = (1 - i)^{2}

What is the answer to 2x-y+(3y-2x)i=2-2i ?
The answer to 2x-y+(3y-2x)i=2-2i is x=1,y=0