What is the answer to (1+2i)(x+yi)-(1+2i)(x-yi)=16 ?

The answer to (1+2i)(x+yi)-(1+2i)(x-yi)=16 is No Solution

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(1+2i)(x+yi)-(1+2i)(x-yi)=16

(1 + 2 i) (x + y i) - (1 + 2 i) (x - y i) = 16

No Solution

Solution steps

(1 + 2 i) (x + y i) - (1 + 2 i) (x - y i) = 16

Expand

(1 + 2 i) (x + y i) - (1 + 2 i) (x - y i) : - 4 y + 2 i y

- 4 y + 2 i y = 16

Rewrite

16

in standard complex form:

16 + 0 i

- 4 y + 2 i y = 16 + 0 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[- 4 y = 16 2 y = 0]

[- 4 y = 16 2 y = 0] : No Solution

No Solution

z^{2} = - 4 i

z^{2} + 2 - 4 i = 0

(x + y i) (2 + i) = 3 - i

x^{2} + 2 i x - 2 = 0

z, z^{2} - (1 - 4 i) z - 4 i = 0

What is the answer to (1+2i)(x+yi)-(1+2i)(x-yi)=16 ?
The answer to (1+2i)(x+yi)-(1+2i)(x-yi)=16 is No Solution