What is the answer to A=P(1+i/(100))^2,i ?

The answer to A=P(1+i/(100))^2,i is A=0,P=0

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A=P(1+i/(100))^2,i

A = P (1 + \frac{i}{100})^{2}, i

A = 0, P = 0

Solution steps

A = P (1 + \frac{i}{100})^{2}

Expand

P (1 + \frac{i}{100})^{2} : \frac{9999 P}{10000} + i \frac{P}{50}

A = \frac{9999 P}{10000} + i \frac{P}{50}

Rewrite

A

in standard complex form:

A + 0 i

A + 0 i = \frac{9999 P}{10000} + i \frac{P}{50}

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[A = \frac{9999 P}{10000} 0 = \frac{P}{50}]

[A = \frac{9999 P}{10000} 0 = \frac{P}{50}] : A = 0, P = 0

A = 0, P = 0

z^{2} = 1 + i + \frac{58}{9 ( 3 - 7 i )}

(x + y i)^{2} = - 8 - 6 i

\frac{i}{- z} = \frac{2 i z}{1 + i}

z^{2} + i z - 1 = 0

2 x - 6 i = - 8 + (20 y) i

What is the answer to A=P(1+i/(100))^2,i ?
The answer to A=P(1+i/(100))^2,i is A=0,P=0