What is the answer to ai+b+4=bi-2i+3a ?

The answer to ai+b+4=bi-2i+3a is a=3,b=5

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ai+b+4=bi-2i+3a

ai + b + 4 = bi - 2 i + 3 a

a = 3, b = 5

Solution steps

ai + b + 4 = bi - 2 i + 3 a

Rewrite

ai + b + 4

in standard complex form:

(b + 4) + ai

(b + 4) + ai = bi - 2 i + 3 a

Rewrite

bi - 2 i + 3 a

in standard complex form:

3 a + (b - 2) i

(b + 4) + ai = 3 a + (b - 2) i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[b + 4 = 3 a a = b - 2]

[b + 4 = 3 a a = b - 2] : a = 3, b = 5

a = 3, b = 5

z^{2} = 8 + 6 i

(2 x - 3 y - 5) + i (x + 2 y + 1) = 0

5 x + 12 y i = - 10 + 4 i

x^{2} + 3 x + 3 - i = 0

x + y i = 0

What is the answer to ai+b+4=bi-2i+3a ?
The answer to ai+b+4=bi-2i+3a is a=3,b=5