What is the answer to A=p(1+i/(100))^2 ?

The answer to A=p(1+i/(100))^2 is A=0,p=0

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A=p(1+i/(100))^2

A = p (1 + \frac{i}{100})^{2}

A = 0, p = 0

Solution steps

A = p (1 + \frac{i}{100})^{2}

Expand

p (1 + \frac{i}{100})^{2} : \frac{9999 p}{10000} + i \frac{p}{50}

A = \frac{9999 p}{10000} + i \frac{p}{50}

Rewrite

A

in standard complex form:

A + 0 i

A + 0 i = \frac{9999 p}{10000} + i \frac{p}{50}

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[A = \frac{9999 p}{10000} 0 = \frac{p}{50}]

[A = \frac{9999 p}{10000} 0 = \frac{p}{50}] : A = 0, p = 0

A = 0, p = 0

9 x - 18 i = - 36 + 6

2 x - y + (2 x - 3 y - 2 - 9) i = 0

z (t) = - 2 i (1 - t) + 2 i t

(a + bi)^{2} = i

∣ z + 3 i ∣ = 4

What is the answer to A=p(1+i/(100))^2 ?
The answer to A=p(1+i/(100))^2 is A=0,p=0