What is the answer to (3x-i)(2+i)+(x-iy)(1+2i)=5+6i ?

The answer to (3x-i)(2+i)+(x-iy)(1+2i)=5+6i is x= 20/17 ,y=-36/17

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(3x-i)(2+i)+(x-iy)(1+2i)=5+6i

(3 x - i) (2 + i) + (x - i y) (1 + 2 i) = 5 + 6 i

x = \frac{20}{17}, y = - \frac{36}{17}

Solution steps

(3 x - i) (2 + i) + (x - i y) (1 + 2 i) = 5 + 6 i

Expand

(3 x - i) (2 + i) + (x - i y) (1 + 2 i) : (7 x + 2 y + 1) + i (- 2 - y + 5 x)

(7 x + 2 y + 1) + i (- 2 - y + 5 x) = 5 + 6 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[7 x + 2 y + 1 = 5 - 2 - y + 5 x = 6]

[7 x + 2 y + 1 = 5 - 2 - y + 5 x = 6] : x = \frac{20}{17}, y = - \frac{36}{17}

x = \frac{20}{17}, y = - \frac{36}{17}

\frac{( 3 + 2 i )}{z ^{2}} = 1

x^{2} + (i - 2) x + (3 - i) = 0

\frac{z}{1 + z} = 3 + 4 i

2 i x x = y

(a + 4 i) (c + 4 i) = 2 + 36 i

What is the answer to (3x-i)(2+i)+(x-iy)(1+2i)=5+6i ?
The answer to (3x-i)(2+i)+(x-iy)(1+2i)=5+6i is x= 20/17 ,y=-36/17