What is the answer to i(x+yi)=(1-6i)(2+3i) ?

The answer to i(x+yi)=(1-6i)(2+3i) is x=-9,y=-20

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i(x+yi)=(1-6i)(2+3i)

i (x + y i) = (1 - 6 i) (2 + 3 i)

x = - 9, y = - 20

Solution steps

i (x + y i) = (1 - 6 i) (2 + 3 i)

Simplify

- y + i x = 20 - 9 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[- y = 20 x = - 9]

[- y = 20 x = - 9] : x = - 9, y = - 20

x = - 9, y = - 20

(a - 2 i)^{2} = 21 - 20 i

x, i = k + \frac{b - x}{x}

\frac{3 b - 2 ai}{4 - 3 i} = 1

(2 + i) x^{2} + (3 - i) x + 1 - 3 i = 0

(x - y) + 3 i = 7 + y i

What is the answer to i(x+yi)=(1-6i)(2+3i) ?
The answer to i(x+yi)=(1-6i)(2+3i) is x=-9,y=-20