What is the answer to (1-i)x+(2+i)y=4+2i ?

The answer to (1-i)x+(2+i)y=4+2i is x=0,y=2

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(1-i)x+(2+i)y=4+2i

(1 - i) x + (2 + i) y = 4 + 2 i

x = 0, y = 2

Solution steps

(1 - i) x + (2 + i) y = 4 + 2 i

Rewrite

(1 - i) x + (2 + i) y

in standard complex form:

(x + 2 y) + (- x + y) i

(x + 2 y) + (- x + y) i = 4 + 2 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x + 2 y = 4 - x + y = 2]

[x + 2 y = 4 - x + y = 2] : x = 0, y = 2

x = 0, y = 2

x - 2 y i = - 1 + 5 i

\frac{2 + i}{z} = \frac{2 + 2 i}{z + i}

x + i y = 3 i - 4

(11 - 3 x) + (7 + 4 y) i = - 17 + i

a + bi + \frac{1}{a + bi} = 0

What is the answer to (1-i)x+(2+i)y=4+2i ?
The answer to (1-i)x+(2+i)y=4+2i is x=0,y=2