What is the answer to (a+6)+2bi=6-5i ?

The answer to (a+6)+2bi=6-5i is a=0,b=-5/2

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(a+6)+2bi=6-5i

(a + 6) + 2 bi = 6 - 5 i

a = 0, b = - \frac{5}{2}

Solution steps

(a + 6) + 2 bi = 6 - 5 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[a + 6 = 6 2 b = - 5]

[a + 6 = 6 2 b = - 5] : a = 0, b = - \frac{5}{2}

a = 0, b = - \frac{5}{2}

(\frac{1 - i}{1 + i})^{100} = a + ib

∣ z - 2 + i ∣ = 2

z^{2} - 4 i z - 1 = 0

(2 x + y) + 6 i = 5 + (x + 4 y) i

z \cdot z + 2 z = 3 + i

What is the answer to (a+6)+2bi=6-5i ?
The answer to (a+6)+2bi=6-5i is a=0,b=-5/2