What is the answer to (-1+i)x+(1+i2)y=1 ?

The answer to (-1+i)x+(1+i2)y=1 is x=-2/3 ,y= 1/3

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(-1+i)x+(1+i2)y=1

(- 1 + i) x + (1 + i 2) y = 1

x = - \frac{2}{3}, y = \frac{1}{3}

Solution steps

(- 1 + i) x + (1 + i 2) y = 1

Rewrite

(- 1 + i) x + (1 + i 2) y

in standard complex form:

(- x + y) + (x + 2 y) i

(- x + y) + (x + 2 y) i = 1

Rewrite

1

in standard complex form:

1 + 0 i

(- x + y) + (x + 2 y) i = 1 + 0 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[- x + y = 1 x + 2 y = 0]

[- x + y = 1 x + 2 y = 0] : x = - \frac{2}{3}, y = \frac{1}{3}

x = - \frac{2}{3}, y = \frac{1}{3}

z^{2} + z = 5 + 5 i

z, z - \frac{1}{z} = 5 + 4 i

x^{2} + (1 - i) x + i = 0

∣ z - i ∣ = 3

∣ z - i ∣ = 4

What is the answer to (-1+i)x+(1+i2)y=1 ?
The answer to (-1+i)x+(1+i2)y=1 is x=-2/3 ,y= 1/3