What is the answer to x+2+3yi=-4x+(y+4)i ?

The answer to x+2+3yi=-4x+(y+4)i is x=-2/5 ,y=2

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x+2+3yi=-4x+(y+4)i

x + 2 + 3 y i = - 4 x + (y + 4) i

x = - \frac{2}{5}, y = 2

Solution steps

x + 2 + 3 y i = - 4 x + (y + 4) i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x + 2 = - 4 x 3 y = y + 4]

[x + 2 = - 4 x 3 y = y + 4] : x = - \frac{2}{5}, y = 2

x = - \frac{2}{5}, y = 2

(2 + i) x - y = 0

i z^{2} + 2 z = z + i

(x^{2} - 9) + (2 y - 5) i = 7 i

x + 3 i + 3 = 5 + y i

z^{2} + (1 - i) \cdot z - i = 0

What is the answer to x+2+3yi=-4x+(y+4)i ?
The answer to x+2+3yi=-4x+(y+4)i is x=-2/5 ,y=2