What is the answer to (1+ai)(1+bi)=b+9i-a ?

The answer to (1+ai)(1+bi)=b+9i-a is

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(1+ai)(1+bi)=b+9i-a

(1 + ai) (1 + bi) = b + 9 i - a

(a = - 1, b = 10 a = 8, b = 1)

Solution steps

(1 + ai) (1 + bi) = b + 9 i - a

Expand

(1 - ab) + i (a + b) = (b - a) + 9 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[1 - ab = b - a a + b = 9]

[1 - ab = b - a a + b = 9] : (a = - 1, b = 10 a = 8, b = 1)

(a = - 1, b = 10 a = 8, b = 1)

(3 x - i) (2 y + i) = - 11 + 7 i

4 + x + 3 i = 8 - (y + 1) i

- \frac{1}{z - i} + 1 - i - z = 0

- 3 + 4 i = (x + i y)^{2}

i (x) = 3 - \frac{4}{2 - x}

What is the answer to (1+ai)(1+bi)=b+9i-a ?
The answer to (1+ai)(1+bi)=b+9i-a is