What is the answer to 1=ai+b,2-i=-a+b ?

The answer to 1=ai+b,2-i=-a+b is a=0,b=1

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1=ai+b,2-i=-a+b

1 = ai + b, 2 - i = - a + b

a = 0, b = 1

Solution steps

1 = ai + b

Rewrite

1

in standard complex form:

1 + 0 i

1 + 0 i = ai + b

Rewrite

ai + b

in standard complex form:

b + ai

1 + 0 i = b + ai

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[1 = b 0 = a]

[1 = b 0 = a] : a = 0, b = 1

a = 0, b = 1

x + y i = 1

z^{2} + 2 i z + i - 1 = 0

(a - bi)^{2} = 13 - 12 i

z^{2} + (1 + i) z - (2 - i) = 0

\frac{5 i}{4 + 9 i} = \frac{a}{b}

What is the answer to 1=ai+b,2-i=-a+b ?
The answer to 1=ai+b,2-i=-a+b is a=0,b=1