What are the solutions to the equation x^2-19x+35=0 ?

The solutions to the equation x^2-19x+35=0 are x=(19+sqrt(221))/2 ,x=(19-sqrt(221))/2

Find the zeros of x^2-19x+35=0

The zeros of x^2-19x+35=0 are x=(19+sqrt(221))/2 ,x=(19-sqrt(221))/2

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x^{2} - 19 x + 35 = 0

x = \frac{19 + 221}{2}, x = \frac{19 - 221}{2}

Solution steps

x^{2} - 19 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

(- 19)^{2} - 4 \cdot 1 \cdot 35 = 221

x_{1, 2} = \frac{- ( - 19 ) \pm 221}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 221}{2 \cdot 1}, x_{2} = \frac{- ( - 19 ) - 221}{2 \cdot 1}

x = \frac{- ( - 19 ) + 221}{2 \cdot 1} : \frac{19 + 221}{2}

x = \frac{- ( - 19 ) - 221}{2 \cdot 1} : \frac{19 - 221}{2}

The solutions to the quadratic equation are:

x = \frac{19 + 221}{2}, x = \frac{19 - 221}{2}

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What are the solutions to the equation x^2-19x+35=0 ?
The solutions to the equation x^2-19x+35=0 are x=(19+sqrt(221))/2 ,x=(19-sqrt(221))/2
Find the zeros of x^2-19x+35=0
The zeros of x^2-19x+35=0 are x=(19+sqrt(221))/2 ,x=(19-sqrt(221))/2