What is the answer to 8+(y+2)i=(x+y)-i ?

The answer to 8+(y+2)i=(x+y)-i is x=11,y=-3

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8+(y+2)i=(x+y)-i

8 + (y + 2) i = (x + y) - i

x = 11, y = - 3

Solution steps

8 + (y + 2) i = (x + y) - i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[8 = x + y y + 2 = - 1]

[8 = x + y y + 2 = - 1] : x = 11, y = - 3

x = 11, y = - 3

p^{2} = 36 i

z + ∣ z ∣ = 25 - 5 i

(3 l + 4) + (3 - m) i = 16 - 3 i

(- 1 + i) a + (1 + 2 i) b = 1

(3 + 2 i) (a + bi) + (5 + 2 i) = 3 - i

What is the answer to 8+(y+2)i=(x+y)-i ?
The answer to 8+(y+2)i=(x+y)-i is x=11,y=-3