What is the answer to 6i=(x+i)(y+i)+1 ?

The answer to 6i=(x+i)(y+i)+1 is x=0,y=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6i=(x+i)(y+i)+1

6 i = (x + i) (y + i) + 1

x = 0, y = 6

Solution steps

6 i = (x + i) (y + i) + 1

Expand

(x + i) (y + i) + 1 : x y + i (x + y)

6 i = x y + i (x + y)

Rewrite

6 i

in standard complex form:

0 + 6 i

0 + 6 i = x y + i (x + y)

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[0 = x y 6 = x + y]

[0 = x y 6 = x + y] : x = 0, y = 6

x = 0, y = 6

i y (2 - i) + 1 = 4 i - x (1 - i)

x^{2} + (i - 6) x + 10 = 0

z^{2} - (1 + i) z + i = 0

x + 2 y + 3 i = 3 + (2 x - y) i

(ii) 6 x^{2} - 24 = 0

What is the answer to 6i=(x+i)(y+i)+1 ?
The answer to 6i=(x+i)(y+i)+1 is x=0,y=6