What is the answer to x+6i=(3-i)+(4-2yi) ?

The answer to x+6i=(3-i)+(4-2yi) is x=7,y=-7/2

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x+6i=(3-i)+(4-2yi)

x + 6 i = (3 - i) + (4 - 2 y i)

x = 7, y = - \frac{7}{2}

Solution steps

x + 6 i = (3 - i) + (4 - 2 y i)

Rewrite

(3 - i) + (4 - 2 y i)

in standard complex form:

7 + (- 1 - 2 y) i

x + 6 i = 7 + (- 1 - 2 y) i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x = 7 6 = - 1 - 2 y]

[x = 7 6 = - 1 - 2 y] : x = 7, y = - \frac{7}{2}

x = 7, y = - \frac{7}{2}

\frac{z + 1}{z - 1} = 2 i

\frac{( - 2 + 9 i )}{( - 6 + i ) ( s )} = - 1

(z - i)^{2} = 2

r (t) = t i + t^{2} j + 2 t k, (2, 4, 4)

x^{2} + x + 1 + i = 0

What is the answer to x+6i=(3-i)+(4-2yi) ?
The answer to x+6i=(3-i)+(4-2yi) is x=7,y=-7/2