What is the answer to (5x-2y)+(8x+10y)i=38+8i ?

The answer to (5x-2y)+(8x+10y)i=38+8i is x=6,y=-4

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(5x-2y)+(8x+10y)i=38+8i

(5 x - 2 y) + (8 x + 10 y) i = 38 + 8 i

x = 6, y = - 4

Solution steps

(5 x - 2 y) + (8 x + 10 y) i = 38 + 8 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[5 x - 2 y = 38 8 x + 10 y = 8]

[5 x - 2 y = 38 8 x + 10 y = 8] : x = 6, y = - 4

x = 6, y = - 4

- (b + 2) i - 8 + a = b - 2 + (3 b - 6) i

3 x - y = i + 2 i x - i y

x + y + (2 x - y) i = 1 + i

∣ 2 z + i ∣ = 4

r, i = \frac{v}{r}

What is the answer to (5x-2y)+(8x+10y)i=38+8i ?
The answer to (5x-2y)+(8x+10y)i=38+8i is x=6,y=-4