What is the answer to (3+3i)(a+bi)=3+18i ?

The answer to (3+3i)(a+bi)=3+18i is a= 7/2 ,b= 5/2

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(3+3i)(a+bi)=3+18i

(3 + 3 i) (a + bi) = 3 + 18 i

a = \frac{7}{2}, b = \frac{5}{2}

Solution steps

(3 + 3 i) (a + bi) = 3 + 18 i

Expand

(3 + 3 i) (a + bi) : (3 a - 3 b) + i (3 a + 3 b)

(3 a - 3 b) + i (3 a + 3 b) = 3 + 18 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[3 a - 3 b = 3 3 a + 3 b = 18]

[3 a - 3 b = 3 3 a + 3 b = 18] : a = \frac{7}{2}, b = \frac{5}{2}

a = \frac{7}{2}, b = \frac{5}{2}

(x + y) + (- y + x) i = 5 + i

+ 8 i z^{2} = 5 - 3 i, z^{1} = 10

(8 - 9 i) y - (2 + 9 i) x = - 40 + 90 i

1 - i = (2 - 2 y + 3 x) + i (- 3 + 2 x + 3 y)

2 x + 4 i y - i x + 5 y = 1 - 7 i

What is the answer to (3+3i)(a+bi)=3+18i ?
The answer to (3+3i)(a+bi)=3+18i is a= 7/2 ,b= 5/2