What is the answer to (3-i)(a+bi)=-6-8i ?

The answer to (3-i)(a+bi)=-6-8i is a=-1,b=-3

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(3-i)(a+bi)=-6-8i

(3 - i) (a + bi) = - 6 - 8 i

a = - 1, b = - 3

Solution steps

(3 - i) (a + bi) = - 6 - 8 i

Expand

(3 - i) (a + bi) : (3 a + b) + i (- a + 3 b)

(3 a + b) + i (- a + 3 b) = - 6 - 8 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[3 a + b = - 6 - a + 3 b = - 8]

[3 a + b = - 6 - a + 3 b = - 8] : a = - 1, b = - 3

a = - 1, b = - 3

(a + i) (2 - bi) = 7 - i

(x + y i) + (2 (x + y i) + 3 i) = 9

\frac{( x + y i )}{i} = (7 + 9 i)

\frac{4 m - 2 i}{3 + ni} = 6 - 2 i

(x^{2} + 6) + (2 x) i = 15 + 6 i

What is the answer to (3-i)(a+bi)=-6-8i ?
The answer to (3-i)(a+bi)=-6-8i is a=-1,b=-3