What is the answer to 9/2 x+(3i)y=0 ?

The answer to 9/2 x+(3i)y=0 is x=0,y=0

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9/2 x+(3i)y=0

\frac{9}{2} x + (3 i) y = 0

x = 0, y = 0

Solution steps

\frac{9}{2} x + (3 i) y = 0

Rewrite

\frac{9}{2} x + (3 i) y

in standard complex form:

\frac{9 x}{2} + 3 y i

\frac{9 x}{2} + 3 y i = 0

Rewrite

0

in standard complex form:

0 + 0 i

\frac{9 x}{2} + 3 y i = 0 + 0 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[\frac{9 x}{2} = 0 3 y = 0]

[\frac{9 x}{2} = 0 3 y = 0] : x = 0, y = 0

x = 0, y = 0

y, (- 2 + 5 i) (1 - i) + (4 + 3 i) = - 6 x + 2 y - 3

x^{2} - 4 x + 4 i = - 1

x + 3 y i = 4 - 5 i

(x - y) + 3 i = - 6 + y i

(x + i y) (6 - 3 i) = 5 + 6 i