What is the answer to (-2-i)(a+bi)=5+3i ?

The answer to (-2-i)(a+bi)=5+3i is a=-13/5 ,b=-1/5

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(-2-i)(a+bi)=5+3i

(- 2 - i) (a + bi) = 5 + 3 i

a = - \frac{13}{5}, b = - \frac{1}{5}

Solution steps

(- 2 - i) (a + bi) = 5 + 3 i

Expand

(- 2 - i) (a + bi) : (- 2 a + b) + i (- a - 2 b)

(- 2 a + b) + i (- a - 2 b) = 5 + 3 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[- 2 a + b = 5 - a - 2 b = 3]

[- 2 a + b = 5 - a - 2 b = 3] : a = - \frac{13}{5}, b = - \frac{1}{5}

a = - \frac{13}{5}, b = - \frac{1}{5}

- 3 x - 7 y i = 9 - 21 i

z^{2} - (1 + i) z + 2 + 2 i = 0

(z - i + 1)^{2} = (2 z + i)^{2}

f, P = L + \frac{s i}{f}

2 (x + i y) = i (2 + 9 i)

What is the answer to (-2-i)(a+bi)=5+3i ?
The answer to (-2-i)(a+bi)=5+3i is a=-13/5 ,b=-1/5