What is the answer to ((2+ai))/(1+i)=real ?

The answer to ((2+ai))/(1+i)=real is a=2,r= 1/(el),\quad r\ne 0,l\ne 0

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((2+ai))/(1+i)=real

\frac{( 2 + ai )}{1 + i} = re a l

a = 2, r = \frac{1}{e l}, r \neq = 0, l \neq = 0

Solution steps

\frac{( 2 + ai )}{1 + i} = re a l

Multiply both sides by

1 + i

\frac{2 + ai}{1 + i} (1 + i) = re a l (1 + i)

Expand

2 + ia = e l a r + e i l a r

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[2 = e l a r a = e l a r]

[2 = e l a r a = e l a r] : a = 2, r = \frac{1}{e l}, r \neq = 0, l \neq = 0

a = 2, r = \frac{1}{e l}, r \neq = 0, l \neq = 0

2 x^{2} = 14 x - 30 i

s i f (x) = - 2 x + 5, E (s, x) = f (1) + f (- 1)

3 z^{2} + (2 - 3 i) z - 1 - 3 i = 0

r (t) = (2 t + 1) i + (t^{2} - 1) j

2 x + 51 = 4 (2 + y i) - 12

What is the answer to ((2+ai))/(1+i)=real ?
The answer to ((2+ai))/(1+i)=real is a=2,r= 1/(el),\quad r\ne 0,l\ne 0