What is the answer to (x+1+i(y-3))/(5+3i)=1+i ?

The answer to (x+1+i(y-3))/(5+3i)=1+i is x=1,y=11

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(x+1+i(y-3))/(5+3i)=1+i

\frac{x + 1 + i ( y - 3 )}{5 + 3 i} = 1 + i

x = 1, y = 11

Solution steps

\frac{x + 1 + i ( y - 3 )}{5 + 3 i} = 1 + i

Multiply both sides by

5 + 3 i

\frac{x + 1 + i ( y - 3 )}{5 + 3 i} (5 + 3 i) = 1 \cdot (5 + 3 i) + i (5 + 3 i)

Simplify

(x + 1) + i (- 3 + y) = 2 + 8 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x + 1 = 2 - 3 + y = 8]

[x + 1 = 2 - 3 + y = 8] : x = 1, y = 11

x = 1, y = 11

v \cdot v = i - 5 j

0 = z + \frac{i}{z}

15 - 28 = 3 l + (4 m) i

+ 4 i z^{2} = 2 + 2 i, z^{1} = 7

\frac{2 + ai}{7 + bi} = 3 + 6 i

What is the answer to (x+1+i(y-3))/(5+3i)=1+i ?
The answer to (x+1+i(y-3))/(5+3i)=1+i is x=1,y=11