What are the solutions to the equation x^2+14=9x ?

The solutions to the equation x^2+14=9x are x=7,x=2

Find the zeros of x^2+14=9x

The zeros of x^2+14=9x are x=7,x=2

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x^{2} + 14 = 9 x

x = 7, x = 2

Solution steps

x^{2} + 14 = 9 x

Move

9 x

to the left side

x^{2} + 14 - 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 9 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 14 = 5

x_{1, 2} = \frac{- ( - 9 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 5}{2 \cdot 1}

x = \frac{- ( - 9 ) + 5}{2 \cdot 1} : 7

x = \frac{- ( - 9 ) - 5}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 7, x = 2

\frac{x - 5}{3} - \frac{x + 1}{4} = 5

(5 x^{2})^{3}

x^{2} + (x - 7)^{2} = 1 3^{2}

\frac{1}{4} b - \frac{1}{5} b > \frac{3}{10} b - \frac{1}{2}

2 x^{2} - 6 x + 4

What are the solutions to the equation x^2+14=9x ?
The solutions to the equation x^2+14=9x are x=7,x=2
Find the zeros of x^2+14=9x
The zeros of x^2+14=9x are x=7,x=2