What is the answer to (x+yi)+(8-5i)=4+3i ?

The answer to (x+yi)+(8-5i)=4+3i is x=-4,y=8

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(x+yi)+(8-5i)=4+3i

(x + y i) + (8 - 5 i) = 4 + 3 i

x = - 4, y = 8

Solution steps

(x + y i) + (8 - 5 i) = 4 + 3 i

Rewrite

(x + y i) + (8 - 5 i)

in standard complex form:

(x + 8) + (y - 5) i

(x + 8) + (y - 5) i = 4 + 3 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x + 8 = 4 y - 5 = 3]

[x + 8 = 4 y - 5 = 3] : x = - 4, y = 8

x = - 4, y = 8

z = 9 e^{i \frac{4 \cdot π}{3}}

z^{2} + 8 - i 6 = 0

\frac{5 + i 2}{( - 1 + i 6 ) x} = - 1

5 i (x + i y) + 3 (x - i y) + i y = - 4 - 5 i

f, i f = M

What is the answer to (x+yi)+(8-5i)=4+3i ?
The answer to (x+yi)+(8-5i)=4+3i is x=-4,y=8