What is the answer to (3a+2i)-(5-2bi)=2-6i ?

The answer to (3a+2i)-(5-2bi)=2-6i is a= 7/3 ,b=-4

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(3a+2i)-(5-2bi)=2-6i

(3 a + 2 i) - (5 - 2 bi) = 2 - 6 i

a = \frac{7}{3}, b = - 4

Solution steps

(3 a + 2 i) - (5 - 2 bi) = 2 - 6 i

Rewrite

(3 a + 2 i) - (5 - 2 bi)

in standard complex form:

(3 a - 5) + (2 + 2 b) i

(3 a - 5) + (2 + 2 b) i = 2 - 6 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[3 a - 5 = 2 2 + 2 b = - 6]

[3 a - 5 = 2 2 + 2 b = - 6] : a = \frac{7}{3}, b = - 4

a = \frac{7}{3}, b = - 4

x^{2} - (1 + 2 i) x + (2 + i) = 0

\frac{5 + 2 i}{z} = 2 - i

\frac{( x + i y )}{( x - i y )} = - i

(x - y) + 5 i = 2 + y i

(z + i) (z - 2 i) = z^{2} + i z + 2

What is the answer to (3a+2i)-(5-2bi)=2-6i ?
The answer to (3a+2i)-(5-2bi)=2-6i is a= 7/3 ,b=-4