What are the solutions to the equation (i2j^3k)*(-ijk)=0 ?

The solutions to the equation (i2j^3k)*(-ijk)=0 are j=0;\quad k\ne 0

Find the zeros of (i2j^3k)*(-ijk)=0

The zeros of (i2j^3k)*(-ijk)=0 are j=0;\quad k\ne 0

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(i 2 j^{3} k) \cdot (- ijk) = 0

j = 0; k \neq = 0

Solution steps

(i 2 j^{3} k) (- ijk) = 0

Simplify

2 k^{2} j^{4} = 0

Divide both sides by

2 k^{2}; k \neq = 0

\frac{2 k ^{2} j ^{4}}{2 k ^{2}} = \frac{0}{2 k ^{2}}; k \neq = 0

j^{4} = 0; k \neq = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

j = 0

The solution is

j = 0; k \neq = 0

+ 10 i e z^{2} = - 9 + 3 i, z^{1} = 10

(\frac{i}{h}) (\frac{4}{3}) = 1

x + y i = 2 + 3 i

x, (i (x - y))^{2} = 2

\frac{2 - i}{z - 1} = 2 + i

What are the solutions to the equation (i2j^3k)*(-ijk)=0 ?
The solutions to the equation (i2j^3k)*(-ijk)=0 are j=0;\quad k\ne 0
Find the zeros of (i2j^3k)*(-ijk)=0
The zeros of (i2j^3k)*(-ijk)=0 are j=0;\quad k\ne 0