What is the answer to xi(x+3y)=(1+yi)(3x+4i) ?

The answer to xi(x+3y)=(1+yi)(3x+4i) is

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xi(x+3y)=(1+yi)(3x+4i)

x i (x + 3 y) = (1 + y i) (3 x + 4 i)

(x = - 2, x = 2, y = - \frac{3}{2} y = \frac{3}{2})

Solution steps

x i (x + 3 y) = (1 + y i) (3 x + 4 i)

Expand

i (x^{2} + 3 x y) = (3 x - 4 y) + i (4 + 3 x y)

Rewrite

i (x^{2} + 3 x y)

in standard complex form:

0 + (x^{2} + 3 x y) i

0 + (x^{2} + 3 x y) i = (3 x - 4 y) + i (4 + 3 x y)

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[0 = 3 x - 4 y x^{2} + 3 x y = 4 + 3 x y]

[0 = 3 x - 4 y x^{2} + 3 x y = 4 + 3 x y] : (x = - 2, x = 2, y = - \frac{3}{2} y = \frac{3}{2})

(x = - 2, x = 2, y = - \frac{3}{2} y = \frac{3}{2})

x^{2} - 3 - 3 i = 0

3 x^{2} + 6 i x = 0

(5 - - 4) - (a + bi) = 6

- 4 i = \frac{1}{( 1000 \cdot x ) i}

i = - 24 t^{2} + 333 t - 32

What is the answer to xi(x+3y)=(1+yi)(3x+4i) ?
The answer to xi(x+3y)=(1+yi)(3x+4i) is