What is the answer to 3i=a+bi ?

The answer to 3i=a+bi is a=0,b=3

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3i=a+bi

3 i = a + bi

a = 0, b = 3

Solution steps

3 i = a + bi

Rewrite

3 i

in standard complex form:

0 + 3 i

0 + 3 i = a + bi

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[0 = a 3 = b]

[0 = a 3 = b] : a = 0, b = 3

a = 0, b = 3

i (x) = \frac{- 4}{5 x + 7}

\frac{1}{z} = i

z^{2} + 2 z + 1 = i

x^{2} + 2 y^{2} + x i + y i = x y + 7 + 3 i

∣ z ∣ + z - z \cdot z = 3 + 3 i