What is the answer to (x-1)i+(y+1)=(1+i)(4-3i) ?

The answer to (x-1)i+(y+1)=(1+i)(4-3i) is x=2,y=6

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(x-1)i+(y+1)=(1+i)(4-3i)

(x - 1) i + (y + 1) = (1 + i) (4 - 3 i)

x = 2, y = 6

Solution steps

(x - 1) i + (y + 1) = (1 + i) (4 - 3 i)

Simplify

(1 + i) (4 - 3 i) : 7 + i

(x - 1) i + (y + 1) = 7 + i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[y + 1 = 7 x - 1 = 1]

[y + 1 = 7 x - 1 = 1] : x = 2, y = 6

x = 2, y = 6

3 x - 5 i = 6 - (10 y) i

z^{2} + z + 2 + i = 0

i zz = 7 + 4 i

x^{2} - (2 + i) x + (- 1 + 7 i) = 0

i (x) = \frac{1}{x + 1}

What is the answer to (x-1)i+(y+1)=(1+i)(4-3i) ?
The answer to (x-1)i+(y+1)=(1+i)(4-3i) is x=2,y=6