What is the answer to (7-7i)-8=x-(2+yi) ?

The answer to (7-7i)-8=x-(2+yi) is x=1,y=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(7-7i)-8=x-(2+yi)

(7 - 7 i) - 8 = x - (2 + y i)

x = 1, y = 7

Solution steps

(7 - 7 i) - 8 = x - (2 + y i)

Rewrite

(7 - 7 i) - 8

in standard complex form:

- 1 - 7 i

- 1 - 7 i = x - (2 + y i)

Rewrite

x - (2 + y i)

in standard complex form:

(x - 2) - y i

- 1 - 7 i = (x - 2) - y i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[- 1 = x - 2 - 7 = - y]

[- 1 = x - 2 - 7 = - y] : x = 1, y = 7

x = 1, y = 7

i (x) = \frac{3}{x + 3}

\frac{1 - i}{1 + z \cdot i} = 2 - 3 i

(9 x^{2} - 9 y^{2}) + 18 x y i = 32 - 24

(2 + 2 i) (x + i y) = (2 + i)^{2}

i (p) = 3500 - 24 p^{2}

What is the answer to (7-7i)-8=x-(2+yi) ?
The answer to (7-7i)-8=x-(2+yi) is x=1,y=7