What are the solutions to the equation 9x^2-24x+12=0 ?

The solutions to the equation 9x^2-24x+12=0 are x=2,x= 2/3

Find the zeros of 9x^2-24x+12=0

The zeros of 9x^2-24x+12=0 are x=2,x= 2/3

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9 x^{2} - 24 x + 12 = 0

x = 2, x = \frac{2}{3}

Solution steps

9 x^{2} - 24 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 9 \cdot 12}{2 \cdot 9}

(- 24)^{2} - 4 \cdot 9 \cdot 12 = 12

x_{1, 2} = \frac{- ( - 24 ) \pm 12}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 12}{2 \cdot 9}, x_{2} = \frac{- ( - 24 ) - 12}{2 \cdot 9}

x = \frac{- ( - 24 ) + 12}{2 \cdot 9} : 2

x = \frac{- ( - 24 ) - 12}{2 \cdot 9} : \frac{2}{3}

The solutions to the quadratic equation are:

x = 2, x = \frac{2}{3}

(x - 1) (x + 4) = 14

2 (- 1)^{3} - 12 (- 1)^{2} - 30 (- 1) + 9

\frac{( 2 n ) !}{n ! n !}

43 + 211

(\frac{1}{1.1})^{2}

What are the solutions to the equation 9x^2-24x+12=0 ?
The solutions to the equation 9x^2-24x+12=0 are x=2,x= 2/3
Find the zeros of 9x^2-24x+12=0
The zeros of 9x^2-24x+12=0 are x=2,x= 2/3