What is the answer to (x-3)+(8-y)i=-3+4i ?

The answer to (x-3)+(8-y)i=-3+4i is x=0,y=4

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(x-3)+(8-y)i=-3+4i

(x - 3) + (8 - y) i = - 3 + 4 i

x = 0, y = 4

Solution steps

(x - 3) + (8 - y) i = - 3 + 4 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x - 3 = - 3 8 - y = 4]

[x - 3 = - 3 8 - y = 4] : x = 0, y = 4

x = 0, y = 4

z^{2} - 2 (1 + 2 i) z + (1 + i) = 0

x + (2 - 3 i) y = 0

z^{2} - (3 + 4 i) z + (1 - 9 i) = 0

C = M (1 + t i)

(1 + i^{2}) x + (3 - i^{5}) y = 1 - i^{3}

What is the answer to (x-3)+(8-y)i=-3+4i ?
The answer to (x-3)+(8-y)i=-3+4i is x=0,y=4