What is the answer to 6i-2j=a(i-j)+b(i+j) ?

The answer to 6i-2j=a(i-j)+b(i+j) is a=4,b=2,\quad j\ne 0

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6i-2j=a(i-j)+b(i+j)

6 i - 2 j = a (i - j) + b (i + j)

a = 4, b = 2, j \neq = 0

Solution steps

6 i - 2 j = a (i - j) + b (i + j)

Rewrite

6 i - 2 j

in standard complex form:

- 2 j + 6 i

- 2 j + 6 i = a (i - j) + b (i + j)

Rewrite

a (i - j) + b (i + j)

in standard complex form:

(- ja + jb) + (a + b) i

- 2 j + 6 i = (- ja + jb) + (a + b) i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[- 2 j = - ja + jb 6 = a + b]

[- 2 j = - ja + jb 6 = a + b] : a = 4, b = 2, j \neq = 0

a = 4, b = 2, j \neq = 0

z, ba rz = i z

z^{2} = 1 - i

(x + 1) + 6 y i = 7 + 18 i

i z^{2} + 2 z + 8 - i = 0

i = \frac{x}{a x + b}, x

What is the answer to 6i-2j=a(i-j)+b(i+j) ?
The answer to 6i-2j=a(i-j)+b(i+j) is a=4,b=2,\quad j\ne 0