What are the solutions to the equation 4v^2+24v=0 ?

The solutions to the equation 4v^2+24v=0 are v=0,v=-6

Find the zeros of 4v^2+24v=0

The zeros of 4v^2+24v=0 are v=0,v=-6

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4 v^{2} + 24 v = 0

v = 0, v = - 6

Solution steps

4 v^{2} + 24 v = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

2 4^{2} - 4 \cdot 4 \cdot 0 = 24

v_{1, 2} = \frac{- 24 \pm 24}{2 \cdot 4}

Separate the solutions

v_{1} = \frac{- 24 + 24}{2 \cdot 4}, v_{2} = \frac{- 24 - 24}{2 \cdot 4}

v = \frac{- 24 + 24}{2 \cdot 4} : 0

v = \frac{- 24 - 24}{2 \cdot 4} : - 6

The solutions to the quadratic equation are:

v = 0, v = - 6

\frac{1 + 2 i}{1 - 2 i}

x - \frac{1}{3} \geq - \frac{3}{2}

\frac{3}{4} (2 x + 1) = 2

x + x + 25 + 3 x + 25 = 180

(\frac{a ^{2}}{b ^{3}})^{5}

What are the solutions to the equation 4v^2+24v=0 ?
The solutions to the equation 4v^2+24v=0 are v=0,v=-6
Find the zeros of 4v^2+24v=0
The zeros of 4v^2+24v=0 are v=0,v=-6