What is the answer to (x-2)+i(y+3)=(x+iy)-(2-i3) ?

The answer to (x-2)+i(y+3)=(x+iy)-(2-i3) is No Solution

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(x-2)+i(y+3)=(x+iy)-(2-i3)

(x - 2) + i (y + 3) = (x + i y) - (2 - i 3)

No Solution

Solution steps

(x - 2) + i (y + 3) = (x + i y) - (2 - i 3)

Rewrite

(x + i y) - (2 - i 3)

in standard complex form:

(x - 2) + (y + 3) i

(x - 2) + i (y + 3) = (x - 2) + (y + 3) i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x - 2 = x - 2 y + 3 = y + 3]

[x - 2 = x - 2 y + 3 = y + 3] : No Solution

No Solution

2 a + bi = 120 - 23 i

(x + y) (2 - 3 i) = - i

(2 - i) z^{2} + (8 i - 6) z + (4 - 7 i) = 0

x^{2} + 2 (1 + i) - 5 (1 + 2 i) = 0

m^{2} = - aji

What is the answer to (x-2)+i(y+3)=(x+iy)-(2-i3) ?
The answer to (x-2)+i(y+3)=(x+iy)-(2-i3) is No Solution