What is the answer to (x+y)+(x-y)*i=6+9*i ?

The answer to (x+y)+(x-y)*i=6+9*i is x= 15/2 ,y=-3/2

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(x+y)+(x-y)i=6+9i

(x + y) + (x - y) \cdot i = 6 + 9 \cdot i

x = \frac{15}{2}, y = - \frac{3}{2}

Solution steps

(x + y) + (x - y) i = 6 + 9 i

Rewrite

(x + y) + (x - y) \cdot i

in standard complex form:

(x + y) + (x - y) i

(x + y) + (x - y) i = 6 + 9 i

Rewrite

6 + 9 \cdot i

in standard complex form:

6 + 9 i

(x + y) + (x - y) i = 6 + 9 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x + y = 6 x - y = 9]

[x + y = 6 x - y = 9] : x = \frac{15}{2}, y = - \frac{3}{2}

x = \frac{15}{2}, y = - \frac{3}{2}

r (t) = t i + (1 - t^{3}) j

(x - i) \cdot (x - 1 - 2 i) = 0

z^{2} + (i - 2) z + (3 + i) = 0

i (x) = x^{2} + 1

z^{2} = 4 (- 1 - i 3)

What is the answer to (x+y)+(x-y)*i=6+9*i ?
The answer to (x+y)+(x-y)*i=6+9*i is x= 15/2 ,y=-3/2