What is the answer to xy+(x-y)i=4 ?

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xy+(x-y)i=4

x y + (x - y) i = 4

(x = 2, y = 2 x = - 2, y = - 2)

Solution steps

x y + (x - y) i = 4

Rewrite

4

in standard complex form:

4 + 0 i

x y + (x - y) i = 4 + 0 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x y = 4 x - y = 0]

[x y = 4 x - y = 0] : (x = 2, y = 2 x = - 2, y = - 2)

(x = 2, y = 2 x = - 2, y = - 2)

∣ z - 1 - i ∣ = 1

x^{2} + 2 (1 + i) x - 5 (1 + 2 i) = 0

i (x) = \frac{640000}{4 - 4}

s i f (x) = 2 - 3 x^{2}

a \cdot (a + bi) = 4 + 6 i