What are the solutions to the equation 7x^2-4x=3 ?

The solutions to the equation 7x^2-4x=3 are x=1,x=-3/7

Find the zeros of 7x^2-4x=3

The zeros of 7x^2-4x=3 are x=1,x=-3/7

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7 x^{2} - 4 x = 3

x = 1, x = - \frac{3}{7}

Solution steps

7 x^{2} - 4 x = 3

Move

3

to the left side

7 x^{2} - 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 7 ( - 3 )}{2 \cdot 7}

(- 4)^{2} - 4 \cdot 7 (- 3) = 10

x_{1, 2} = \frac{- ( - 4 ) \pm 10}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 10}{2 \cdot 7}, x_{2} = \frac{- ( - 4 ) - 10}{2 \cdot 7}

x = \frac{- ( - 4 ) + 10}{2 \cdot 7} : 1

x = \frac{- ( - 4 ) - 10}{2 \cdot 7} : - \frac{3}{7}

The solutions to the quadratic equation are:

x = 1, x = - \frac{3}{7}

16 x^{2} + 8 x

d = (30 - 23)^{2} + (- 5 - (- 8))^{2}

1 + 49 a^{2} - 14 a

\frac{2 ^{5}}{6 ^{5}}

9 x^{2} - 18 x - 7

What are the solutions to the equation 7x^2-4x=3 ?
The solutions to the equation 7x^2-4x=3 are x=1,x=-3/7
Find the zeros of 7x^2-4x=3
The zeros of 7x^2-4x=3 are x=1,x=-3/7