What is the answer to (5x+4)+7i=(3y+1)i+9 ?

The answer to (5x+4)+7i=(3y+1)i+9 is x=1,y=2

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(5x+4)+7i=(3y+1)i+9

(5 x + 4) + 7 i = (3 y + 1) i + 9

x = 1, y = 2

Solution steps

(5 x + 4) + 7 i = (3 y + 1) i + 9

Rewrite

(3 y + 1) i + 9

in standard complex form:

9 + (3 y + 1) i

(5 x + 4) + 7 i = 9 + (3 y + 1) i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[5 x + 4 = 9 7 = 3 y + 1]

[5 x + 4 = 9 7 = 3 y + 1] : x = 1, y = 2

x = 1, y = 2

(x + i y)^{2} - x - i y + i (x - i y) = 0

(1 + 5 i) p - 2 q = 3 + 7 i

x + y i = 3 - 2 i

(x + i y)^{2} - 3 i (x + i y) - 2 = 0

2 + i y = x - 2 i

What is the answer to (5x+4)+7i=(3y+1)i+9 ?
The answer to (5x+4)+7i=(3y+1)i+9 is x=1,y=2