What is the answer to (1+x)=(1+r)*(1+i) ?

The answer to (1+x)=(1+r)*(1+i) is r=-1,x=-1

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(1+x)=(1+r)*(1+i)

(1 + x) = (1 + r) \cdot (1 + i)

r = - 1, x = - 1

Solution steps

(1 + x) = (1 + r) (1 + i)

Rewrite

(1 + x)

in standard complex form:

(1 + x) + 0 i

(1 + x) + 0 i = (1 + r) (1 + i)

Rewrite

(1 + r) \cdot (1 + i)

in standard complex form:

(1 + r) + (1 + r) i

(1 + x) + 0 i = (1 + r) + (1 + r) i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[(1 + x) = 1 + r 0 = 1 + r]

[(1 + x) = 1 + r 0 = 1 + r] : r = - 1, x = - 1

r = - 1, x = - 1

x^{2} - 8 x i - 25 = 0

(x + i y) + 2 (x - i y) = \frac{2 i}{1 + 3 i}

3 i y^{2} - y + 2 i = 0

x (1 + i)^{2} + y (2 - i)^{2} = 3 + 10 i

z^{2} - (5 + 2 i) z + 2 = 0

What is the answer to (1+x)=(1+r)*(1+i) ?
The answer to (1+x)=(1+r)*(1+i) is r=-1,x=-1