What is the answer to (4i)/(-6+4i)= a/b ?

The answer to (4i)/(-6+4i)= a/b is a=0,b=0

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(4i)/(-6+4i)= a/b

\frac{4 i}{- 6 + 4 i} = \frac{a}{b}

a = 0, b = 0

Solution steps

\frac{4 i}{- 6 + 4 i} = \frac{a}{b}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

4 ib = (- 6 + 4 i) a

Expand

(- 6 + 4 i) a : - 6 a + 4 ia

4 ib = - 6 a + 4 ia

Rewrite

4 ib

in standard complex form:

0 + 4 bi

0 + 4 bi = - 6 a + 4 ia

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[0 = - 6 a 4 b = 4 a]

[0 = - 6 a 4 b = 4 a] : a = 0, b = 0

a = 0, b = 0

\frac{15}{z - 1} = - 6 - 3 i

(x - 2) i = y - 3 i

z^{2} + (2 - 2 i) z - (4 + 2 i) = 0

x + 2 - 3 i y = 0

\frac{z - i}{z - 2} = 2

What is the answer to (4i)/(-6+4i)= a/b ?
The answer to (4i)/(-6+4i)= a/b is a=0,b=0